Question

Possible negative, positive, and complex numbers?

f(x) = –2x3 – 5x2 – 6x + 4

Answer 1

?

Answer 2

I meant zeros... my bad

Answer 3

if A, B, C are zeroes then
for a cubic polynomial;
\[x^3+(A+B+C)x^2+(AB+BC+CA)x+ABC=0.\]
now u can put the values:)

Answer 4

A+B+C=5/2
AB+BC+CA=6/2=3
ABC=-4/2=-2.
NOW JUST FIND:)
A, B, C.

Answer 5

Got it or not?
Plz tell when u understand this?
& Ask doubt if u have^_^

Answer 6

not... :s

Answer 7

where is ur doubt?

Answer 8

x3+(A+B+C)x2+(AB+BC+CA)x+ABC=0 .... I dont get this part..

Answer 9

A+B+C IS x^2's coefficent ^ so on

Answer 10

it is a form of representing cubic polynomial just as in quadratic
\[x^2-(A+B)+AB=0.\]
if A & B are its zeroes

Answer 11

question... is it 2 or 0 positive... 1 negative... and 0 or 2 complex?

Answer 12

sorry i can't do that; I don't know how to that:)
but i gave u what I knew

Answer 13

ok thanks

Answer 14

:)