Without drawing the graph of the equation, determine how many points the parabola has in common with the x-axis and whether its vertex lies above, on, or below the x-axis.

y = 2x^2 + x - 3

A. 1 point in common; vertex on x-axis

B. 2 points in common; vertex below x-axis

C. 2 points in common; vertex above x-axis

D .no points in common; vertex below x-axis

Question

Without drawing the graph of the equation, determine how many points the parabola has in common with the x-axis and whether its vertex lies above, on, or below the x-axis.

y = 2x^2 + x - 3

A. 1 point in common; vertex on x-axis

B. 2 points in common; vertex below x-axis

C.  2 points in common; vertex above x-axis

D .no points in common; vertex below x-axis

anonymous · Answer

It is below the x-axis and therefore has 2 intersections with the x-axis since the squared term is positive. You can find the vertex by using the formula -b/2a to find the x and then by plugging it in for y.

anonymous · Answer

Lol So Which One Is it?

anonymous · Answer

i think you should make your sister do her own work? don't you? 
let her make the decision according to the hints posted by the helpers....

anonymous · Answer

I want to know the answer and i will explain it to her

mertsj · Answer

Would you agree that the parabola is concave upward?