Question

What are the approximate solutions of 4x^2 + 3 = −12x to the nearest hundredth?

x ≈ −3.23 and x ≈ 0.23

x ≈ −2.72 and x ≈ −0.28

x ≈ 0.28 and x ≈ 2.72

x ≈ −0.23 and x ≈ 3.23

Answer 1

\[4x^2 + 3 = −12x \]Convert this equation to standard polynomial form.\[4x^2 + 12x + 3 =0\]Solve forx.

Answer 2

* for x.