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since the dimensions of the smaller triangle is 2/7 that of the big triangle, the area should be (2/7)^2 , or 4/49, of the bigger one... since the big triangle has area 20, take 4/49 of that for the area of the smaller triangle.
the area of the smaller triangle is 4/49 of the big one...
solve this proportion: \(\large \frac{x+3}{5}=\frac{4x-4}{4} \)
by similar triangles...
yes...:)
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