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OpenStudy (anonymous):
solve for x: log2x + log(x-1) = log6x
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OpenStudy (anonymous):
4?
OpenStudy (anonymous):
I assume they are same base?
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
x = 0 , x =4
OpenStudy (anonymous):
Thanks!
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OpenStudy (anonymous):
Yep, only x = 4 accepted!
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