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Please help! Find the third term of the sequence a_1=12, a_(n+1)=(a_n)/(n+1
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Is this an AP? That thing you wrote for the nth term seems odd - could you check that out please?
Hmm... Yes, it's the problem word for word. :/
Can you help or does it not make sense? :/
well, \[a_n = \frac{a_{n-1}}{n}\]and \[a_1 =12 ~~\rightarrow given\] so, \[a_2 = a_1/2 = 12 /2\] and hence, \[a_3 = a_2/3\] helps?
6. THANKS APOORVK!
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actually it's 12/2/3 = 6/3 = 2. @mathsux4real
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