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OpenStudy (anonymous):
find the least number between 200 and 500 which leaves a remainder of 3 in each case when divided by 8,10,12 and 30
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OpenStudy (anonymous):
it is 243 for 8*5*3=120 and 240 is the least number which is the integer multiple of 120 between 200 and 500 then plus 3
OpenStudy (anonymous):
Thank you
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