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Mathematics 17 Online
OpenStudy (anonymous):

find the least number between 200 and 500 which leaves a remainder of 3 in each case when divided by 8,10,12 and 30

OpenStudy (anonymous):

it is 243 for 8*5*3=120 and 240 is the least number which is the integer multiple of 120 between 200 and 500 then plus 3

OpenStudy (anonymous):

Thank you

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