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Physics 7 Online
OpenStudy (anonymous):

For a heater rated 4 kW and 220 V calculate the resistance of the heater

OpenStudy (anonymous):

220/18.18

OpenStudy (anonymous):

I'd guess the relevant formulas are\[V=IR\]and\[P=I^2R\] P and V are known so solve the system of I and R.

OpenStudy (anonymous):

I think Ajay's 18.18 is a rounded-off value. It would be more exact to use \[R=V^2/P\]

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