Question

Look at the rhombus ABCD.




Maddox made the following table to prove that diagonal AC of rhombus ABCD bisects its angles.




Statements


Justifications




1.ABCD is a Rhombus


1.Given




2. AB = BC = CD = DA


2. CPCTC




3. AC = AC


3.reflexive property




4. Triangle ABC is congruent to triangle ACD


4. SSS postulate




5. Angle BAC = angle DAC, angle BCA = angle DCA


5. definition of rhombus



Which two justifications did Maddox interchange while making the table?

Answer 1

someone please

Answer 2

i think its 4 and 5, but m not sure

Answer 3

ok thanks