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Simplify the following (-8a^3b^4)2
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\[(-8a^3b^4)^2=(-8)^2a^{3\times2}b^{4\times2}=\cdots\]
how do I simplify if there are no other terms besides the paren- nevermind o_o
remember negative times negative is positive
I dont think this is right but I got -8a^6b^8
oh wait positive 8... sorry accidentally hit the "-" sign
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almost the only bit you got wrong was \[(-8)^2=-8\times-8\neq-8\]
\[(-8)^2=-8\times-8\neq8\]
8x8? wouldn't that be 64?
\[(-8)^2=-8\times-8=8\times8=\cdots\]
yeap, you got it
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thanks.
what was your final answer
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