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∫ x(x-4)^9 dx
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so i let u=x-4 and du=dx x=u+4 So ∫ u+4(u)^9 du is it right so far??
yep...
\(\large \int {x(x-4)^9}dx \rightarrow \int {(u+4)u^9}du\rightarrow \int{u^{10}+4u^9du}\)
great that makes sense thanxs
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