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Find the area of an equilateral triangle (regular 3-gon) with the given measurement. 6-inch side. A = sq. in.
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30 60 90 triangle. So x = 3 Thus:: 6 * 3 sqrt 3 /2
\[A = \frac14s^{2}√3\]
I find that memorizing this formula is really helpful. :)
9 sqrt 3 final answer.
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