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Will someone show their work on this problem. 2x/x^2-4 = 4/x^2-4 - 3/x+2 I got No Solution which is the correct answer but I want to make sure I did the problem correctly.
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Is it \[ \frac{2 x}{x^2-4}=\frac{4}{x^2-4}-\frac{3}{x+2 } \]
Yes and how are you doing that so neatly?
Uusing LaTeX
Your equation does not have a solution.
did you get 15x=0? which is no solution
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