Question

\frac{2
x}{x^2-4}=\frac{4}{x^2-4}-\frac{3}{x+2
}
Will someone solve this?

Answer 1

\[{2x \over x^2 - 4} = {4 \over x^2 - 4} - {3 \over x + 2}\] ?

Answer 2

\[{2x \over (x+2)(x-2)} = {4 \over (x+2)(x-2)} - {3 \over x + 2}\]

Answer 3

Multiply each side by (x + 2)(x - 2) to get:
\[2x = 4 - 3(x-2)\]

solve from there