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How about we bring everything to the left side first?
\[y^2 -1= (y+1)(y-1)\]
I tried that but I just confused myself in the end..
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Ok I'll simplify this for you.
otayy
OS is not being responsive.
\[\frac{y+2}{y+1}\times(y-1)(y+1)+\frac{2y^2-y+3}{y^2-1}\times(y-1)(y+1)+\frac{y-2}{y-1}\times(y-1)(y+1)\]
\[(y+2)(y-1)+2y^2-y+3+(y-2)(y+1)=0\]
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\[y^2+y-2+2y^2-y+3+y^2-y-2=0\]
\[4y^2-y-1=0\]
Use the quadratic formula. a = 4, b = -1, c = -1
|dw:1339290146217:dw|
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