Question

integral of 3x^2 * sin(x^3)dx

Answer 1

I did\[ u = x^3\]
\[du = 3x^2 dx\]

\[\int\limits \sin(u) du\]

-cos(u) + c

\[-\cos(3x^2) + c\] but apparently that is wrong?

Answer 2

Oh wait... it should be -cos(x^3) + c

Answer 3

yes because u equals x^3 not 3x^2 :)

Answer 4

Yeah stupid mistake late at night :D.

Answer 5

it happens to all man