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Find the area of the surface generated by revolving the curve about the indicated axis. y=(x^3)/14, 0<=x<=4, x axis
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\[S=2\pi \int_{a}^{b}f(x)\sqrt{1-\left[f'(x)\right]^2}dx\] for a function \(f(x)\) rotated about the \(x\)-axis from \(x=a\) to \(x=b\).
I was a little confused by that.
@roj3og , can you use the formula I just provided? :)
that was what i was working with. this is what I have so far in the next window.
I will simultaneously work out my own solution to compare. :)
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