At the start of a basketball game, the referee tosses a ball into the air for the jump ball. The equation that models the height of the ball is h(t) = -16t2 + 30t + 8. During what time interval is the height of the ball above 10 feet? (Round your answer to the nearest tenth of a second.) a) Between 1.1 and 1.6 seconds b) Between 0.1 and 1.8 seconds c) Between 0.3 and 2.1 seconds
Well, \(-16t^{2}+30t+8=10 => -16t^{2} +30t-2=0\) Then solve for the time \(t\)
Using the quadratic formula.
\[\frac{-(b)\pm\sqrt{(b)^{2}-4(a)(c)}}{2a} \]
I guest have no choice but, to learn how to master Quadratic Formula
You don't know how to use the Quadratic FOrmula? It's basically subbing in numbers.
b)Between 0.1 and 1.8 seconds. is my educate guess i lost trace
Join our real-time social learning platform and learn together with your friends!