Ask your own question, for FREE!
Mathematics 7 Online
OpenStudy (anonymous):

Select the counterexample that makes this conjecture false: For any real number x, x2 ≥ x.

OpenStudy (anonymous):

x = 0

OpenStudy (anonymous):

x = -2

OpenStudy (anonymous):

x = ½

OpenStudy (anonymous):

x = |3|

OpenStudy (anonymous):

I need help,Which would it be out of those 4 answers?

OpenStudy (anonymous):

1/2

OpenStudy (anonymous):

is that \[x^2\]

OpenStudy (anonymous):

x2<x x2-x<0 x(x-1)<0

OpenStudy (anonymous):

if you square a number it will be positive

OpenStudy (anonymous):

x lies b/n 0 & 1

OpenStudy (anonymous):

yes its that gner

OpenStudy (anonymous):

its 1/2?

OpenStudy (anonymous):

yup

OpenStudy (anonymous):

thank you so much avinash and gmer :)

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!