Question

4/x-2=-3/x+5 + 7/(x+5)(x-2)

How do you go about solving this equation? Please show step by step. Thank you.

Answer 1

both time (x+5)(x-2) in two sides, then we can have
4(x+5)=-3(x-2)+7

move -3(x-2) to right
4(x+5)+3(x-2)=7

spread it
4x+20+3x-6=7

keep only x one side
4x+3x=7-20+6

combin it
7x=-7
then x=-1

Answer 2

move -3(x-2) to left

Answer 3

so if you multiply the right side by x+5 does it take care of both the x+5's? if that makes sense?

Answer 4

I'm trying to figure out what you have to do to get rid of the x+5 under the 7?

Answer 5

multiply (x+5)(x-2)
(x+5)(x-2) is one part

Answer 6

not only (x+5) or (x-2)

Answer 7

Okay I see I think ...

Answer 8

Thank you!

Answer 9

:)