Question

Solve the system: 3x^2 - 6y^2 = 9 and x^2 + 5y^2 = 53

Answer 1

3x^2 - 6y^2 = 9
x^2 + 5y^2 = 53 Multiply 3
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Elimination
3x^2 - 6y^2 = 9
3x^2 + 15y^2 = 159
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-21y^2=-150
y^2=50/7
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\[~~~~~~~~~~~~~~~~~~ y= \pm \sqrt{\frac{50}{7}}\]
Substitute this 'y' values to 3x^2 - 6y^2 = 9 and find the other 2 values of x