Question

Find the area of a right triangle with leg 45 and a hypotenuse of 51.

Answer 1

if i remember right the equation for the area of a triangle is (base*height)/2, so use a^2 + b^2 = c^2 find the other leg and solve

Answer 2

\[a ^{2}+b ^{2}=c ^{2}\]
\[a ^{2}+45^{2}=51^{2}\]
\[a ^{2}+2025=2601\]
\[a ^{2}=576\]
\[\sqrt{a ^{2}}=\sqrt{576}\]
\[a=24\]

The third leg is 24.