Question

4x-1=4x^2 find the solution, step by step please.

Answer 1

\[4x ^{2}-4x+1=0\]
split the middle term.. so you have
\[4x ^{2}-2x-2x+1=0\]
then factor them separately..
\[2x(2x-1)-(2x-1)\]
so then the answer is:
\[(2x-1)(2x-1) = 0\]
all you have to do now is equate (2x-1) to 0.
\[2x-1=0\]\[2x=1\]\[x=1/2\]

Answer 2

oh im sorry i forgot to put the negetive in front of the 4x^2