Question

Solve 15x^4-28x^2+5=0

Answer 1

fatorize it to get the value of x.

Answer 2

To make things easier, x^2 = y

15y^2 - 28y + 5 = 0

Answer 3

I'm confused im sorry...my brained is fried

Answer 4

@saifoo.khan

Answer 5

If you wanted to try you may proceed, i didn't wanted to interrupt. :) @goformit100

Answer 6

saifooo! did you switch with lbg whatever?

Answer 7

factor as \((3 x^2-5) (5 x^2-1) = 0\) and work from there.
someone is looking a lot like saifoo these days

Answer 8

Dang! my PC froze.

Answer 9

Ok ;-)

Answer 10

freezing my pc off here too

Answer 11

@satellite73 , People are following my footsteps to be on 99. :D
ANd im following your steps to get on 100. :D

Answer 12

shh.

Answer 13

;)

Answer 14

@alisa845 you got this? set each factor = 0, solve for \(x^2\) and then solve for \(x\)

Answer 15

15x^2-25x^2-5

Answer 16

Is that correct?