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Factor completely: 12x2 − 27 (4x − 9)(3x + 3) (4x − 9)(3x − 3) 3(2x − 3)(2x + 3) 3(2x − 3)(2x − 3)
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Kay, remove what we can remove..in this case, we can remove the 3.
is it A
Then we are left with 3(4x+9)
No..you cannot forget the 3 we removed.
okay whats next
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3(4x^2+9) now factor it So that leaves us with 3(2x − 3)(2x + 3)
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