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Solve. 16x^2-8x-3=0
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factor out the number
you already got the first number which ( x + ) (x -3)
\[16x^2-8x-3\]
-16x is incorrect
=>\[16x^2+4x-12x-3\]
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=>\[4x(4x-1)-3(4x-1)\]
=>\[(4x-3)(4x-1)\]
x=3/4 || x=-1/4
last number is +3 support to be -3
that is the final answer
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K!it's avery confusin ques
@Andresfon12 x=1/4
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