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Mathematics 15 Online
OpenStudy (anonymous):

Solve. 16x^2-8x-3=0

OpenStudy (anonymous):

factor out the number

OpenStudy (anonymous):

you already got the first number which ( x + ) (x -3)

OpenStudy (theviper):

\[16x^2-8x-3\]

OpenStudy (anonymous):

-16x is incorrect

OpenStudy (theviper):

=>\[16x^2+4x-12x-3\]

OpenStudy (theviper):

=>\[4x(4x-1)-3(4x-1)\]

OpenStudy (theviper):

=>\[(4x-3)(4x-1)\]

OpenStudy (anonymous):

x=3/4 || x=-1/4

OpenStudy (anonymous):

last number is +3 support to be -3

OpenStudy (anonymous):

that is the final answer

OpenStudy (theviper):

K!it's avery confusin ques

OpenStudy (theviper):

@Andresfon12 x=1/4

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