Given: In ∆ABC, segment DE is parallel to segment AC . Prove: BD over BA equals BE over BC The two-column proof with missing statements and reasons proves that if a line parallel to one side of a triangle also intersects the other two sides, the line divides the sides proportionally. Statement Reason 1. segment DE is parallel to segment AC 1. Given 2. Line segment BA is a transversal that intersects two parallel lines 2. Conclusion from Statement 1 3. 3. 4. ∡BDE ≅ ∡BAC 4. Reflexive Property of Equality 5. ∆ABC ~ ∆DBE 5. Angle-Angle (AA) Similarity Postulate 6. 6. Complete the proof by entering the correct statements and reasons.
so this isn't multiple choice and it's more like type in the answer?
yea ..can u help??
yeah just need to think of the right wording, one sec
omg ur amazing thank you! lol ill wait take ur time:)
ugh, had a glitch, one sec while I retype, so sorry about that
basically in step 4, they're using the symmetric property and not the reflexive property...not sure why they made this mistake So to get to step 4, we need to get ∡BAC ≅ ∡BDE for step 3 (this is just the flipped version of step 4) So the answer for the first part of step 3 is ∡BAC ≅ ∡BDE The justification for this step is that a transversal line creates corresponding congruent angles -------------------------------- In step 5, we prove that the triangles are similar So in step 6, we can say that the corresponding sides are proportional Therefore, the answer for the first part in step 6 is BD over BA equals BE over BC and the justification for this step is Side-Side-Side Similarity Theorem again sry about that
haha no need for sorry hun!
hopefully all that makes sense and that you're able to input it the way they want it
its perfect thank you so much ..ur awesome:)
you're very welcome
<3
aww I'm touched lol
...or that could be ice cream...either way, sweet
hahaha both would be good! lol ..i want some ice cream now! lol hmmm
yes ice cream is always good no matter what time it is
haha ikr! ...i think i have some chocolate in the freezer! lol
lol then it's time to dive in, that sounds really delicious
hahaha come on over! lol
lol it's time to have an ice cream party
makes me wish I had some ice cream, lol I'm making myself hungry
hahaha ice cream party sounds fun! lol ...haha ikr! im to lazy to get up and go get some tho! lmao
lol so basically I have a better chance of getting at it than you do?
hahahahaha yes! i cant tell u how comfortable i am in my bed right now! lol
that makes sense, once I'm comfy in bed, I can't get out too
haha yea ...ice cream isnt that important! lol
lol I can see it folding its arms in the background saying "fine, I see how it is"
haha sorry....i would get up and get u some ice cream if u were here! lol
lol no i can manage on my own, so it's all good
haha ok ..good i didnt wanna get up anyways! lol
lol i knew that
haha u must be psychic or something! lmao:P
lol i wish
so where u from?
I'm born and raised in CA, still living here as well
cool i was born in Portugal and now i live in Florida! lol
very cool, I've been as close to florida since I passed through georgia, but have never been even close to portugal lol
haha yea i love it here we have nice beaches! ...yea alot of people havent my dad was in the military so thats why i was born there !
ah so you've basically seen most of the world then?
yes i have ive been alot of places!
my understanding (probably flawed though?) is that military families move a lot all over the world.
yes most of the time but not always! ..but my dads out of the military now so we r here for good! lol
oh very cool, seeing the world is great (don't get me wrong), but settling in a nice home is much much better.
yes i agree! but i dont remember alot of the traveling bc i was very little!
Ah that's a pity, but then again, you probably didn't have to deal with the hassles of changing schools and such. So that's good.
yea ur right! ..hey i have to go to bed its 1pm her! and im tired! but if ur on tomorrow message me:) ..it was nice to meet u my name is anna btw
Nice to meet you Anna, you obviously already know (from my username), but I might as well make it formal lol: I'm Jim. Yeah I'm not thinking of the time difference, lol it's really late over there.
Feel free to message me if you need any more help. You can also email me if you want if I'm not on and I might get to it much quicker.
ok jim well ill message u and then u can give me ur email:)
alright sounds good
@Coolsector
For those who see this and was as confused as I was it is 3. ∠ BDE ≅ ∠ BAC; Corresponding Angles Postulate 5. ΔBDE ~ ΔBAC; Angle-Angle (AA) Similarity Postulate
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