Question

HELP PLEASE


29. Find a pair of factors for each number using the difference of two squares.
a. 45
b. 77
c. 112

Answer 1

Different squares is a^2-b^2
a^2-b^2=(a-b)(a+b)
45
=49-4
=7^2-2^2
=(7-2)(7+2)
=5*9
Therefore factors of 45 5 nd 9.
77
=81-4
=9^2-2^2
=(9-2)(9+2)
=7*11
Therefore factors of 77 7 nd 11.
112
=121-9
=11^2-3^2
=(11-3)(11+3)
=8*14
Therefore factors of 77 8 nd 14.

Answer 2

is that clear?

Answer 3

yes thank you so much. i've been trying to work this all night.

Answer 4

u r welcome.