two blocks A and B each of mass m are placed on a smooth horizontal surface . two horizontal forces F and 2F are applied on both the blocks A and B respectively. Block A does not slide over block B. Then the normal reaction force acting between the blocks is?
a)F
B)F/2
C)F/(sqrt of 3)
d) 3 F
answer is 3F. Can anyone guide me how to get there?

Question

two blocks A and B each of mass m are placed on a smooth horizontal surface . two horizontal forces F and 2F are applied on both the blocks A and B respectively. Block A does not slide over block B. Then the normal reaction force acting between the blocks is? 
a)F
B)F/2
C)F/(sqrt of 3)
d) 3 F
answer is 3F. Can anyone guide me how to get there?

anonymous · Answer

i think two bodies on same plane slide in same direction, so these two forces get added and it'll be 3F. If i'm wrong then tell me the correct solution on ma blog ....