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Write the general conic form equation for a parabola with vertex at (2, 2) and focus at (1/2, 2). i got this y² - 4y + 2x = 0 Other choices y² - 4y + 6x - 8 = 0 y² - 4y - 6x + 16 = 0
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What is the focus?
1/2,2
x=-(y-k)^2+h x=-(y-2)^2+2 x=-y^2+4y-4+2 -y^2+4y-2-x=0 or y^2-4y+2+x=0
thanks mertsj
yw
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