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A 0.300 kg baseball is thrown in a straight line through the air. At a height of 4.5 m above the surface of the earth, it has speed of 15.0 m/s. what is the total mechanical energy of the baseball?
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\[\frac12mv^2 + mgh = .3\left(\frac12 15\cdot 15 + 4.5 \cdot 10\right)\]
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