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OpenStudy (jaggu):
wht is Integration of 1/(sec x+1)..?
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OpenStudy (aravindg):
:)
OpenStudy (aravindg):
ready for integrating?
OpenStudy (aravindg):
shall i start?
OpenStudy (jaggu):
yaa
OpenStudy (jaggu):
r u doing sir
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OpenStudy (jaggu):
wht u ..have written ksaimouli..sry I didn't got it...:(
OpenStudy (aravindg):
\[\huge\int\limits \frac{dx}{1+\sec\;x}\]
\[\Large =\int\limits \frac{1dx}{1+\frac{1}{\cos x}}\]
\[\Large=\int\limits\limits \frac{1dx}{\frac{1+\cos x}{\cos x}}\]
\[\Large =\int\limits \frac{\cos xdx}{1+\cos x}\]
OpenStudy (aravindg):
hmm ...do u get any idea frm here?
OpenStudy (jaggu):
yes sir..
after this wht we have to do..?
OpenStudy (aravindg):
try multiplying numerator and denominator by 1-cos x
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OpenStudy (jaggu):
okkgot it sir thnxs a lot sir..
OpenStudy (jaggu):
can I ask one more ques..
OpenStudy (aravindg):
:) welcomes!!
OpenStudy (aravindg):
yep bt pls post it separately
OpenStudy (jaggu):
can I ask here only..
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OpenStudy (aravindg):
post it separately bcoz long qns laggs the site ,well call me by using @AravindG
OpenStudy (anonymous):
\[\int\limits_{}{1/(1+\sec x)} = x- \tan (x/2)+c\]
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