Question

f(x)=1/4(x+5)^2+9

Answer 1

vertex? line symmetry?Min/max of f(x)?

Answer 2

\(\large f(x)=\frac{1}{4}(x+5)^2+9 \)
this parabola has vertex at (-5, 9), x=-5 is the axis of symmetry.
since the coefficient of the x^2 term is positive, the parabola opens upwards which means the vertex is a minimum