Question

How do you solve :
What is the sum of the polynomials
3a2b + 2a2b2 and –ab2 + a2b2 ?

Answer 1

it is:
\[3a^{2}b+2a^{2}b^{2} -ab^{2} + a^{2}b^{2} = 3a^{2}b^{2} + 3a^2b-ab^2\]
From there, you could remove the GCFs if necessary.

Answer 2

why though how did you solve this

Answer 3

because the like terms, with both a and b squared, can be combined. like adding x + 2x = 3x

Answer 4

none of these are ur answer

A. 3a2b – ab2 + 3a2b2
B. 3a2b – ab2 + 2a2b2
C. 2a2b + 3a2b2
D. 2a2b3 + 2a4b4
E. –3a3b3 + 2a4b

Answer 5

3a2b – ab2 + 3a2b2 is the same, just a different order. So it is A.