The length of a rect. is 6 more than 4 times the width. the perimete is 62. find the dimensions of the rectangle.

Question

The  length of a rect. is 6 more than 4 times the width. the perimete is 62. find the dimensions of the rectangle.

anonymous · Answer

i keep getting it wrong

anonymous · Answer

x should equal 5 but i got 29

apoorvk · Answer

wait. i made a mistake. didn't read it carefully.

anonymous · Answer

yeah it should be 4x+6

anonymous · Answer

or 6(4x)

myininaya · Answer

more means add

apoorvk · Answer

let the rectangle's width be 'x'.
Then, length = 6 more than 4 times the width= 4x +6
Perimeter = 62 = 2(length + breadth)

put in the values of length and the breadth on terms of 'x', and find 'x' by solving the equation.

anonymous · Answer

yeah so 4x+6 but i tried that and it didnt wrk

myininaya · Answer

so L is  6 more than 4 times the width is  
    L =  6  +  4 W

myininaya · Answer

Then use the formula for perimeter since the perimeter is given
2L+2W=62

anonymous · Answer

i got 11.2 and thats not the answer ok ll try that

anonymous · Answer

IT WORKED!! thanks muninaya!

apoorvk · Answer

actually you will get x=5 alright, if you do this correctly.