Question

Simplify 125 to the power of negative 2 over 3

Answer 1

\[\Large 125^{-\frac{2}{3}}\]

\[\Large \frac{1}{125^{\frac{2}{3}}}\]

\[\Large \frac{1}{\left(\sqrt[3]{125}\right)^{2}}\]

\[\Large \frac{1}{\left(\sqrt[3]{5^3}\right)^{2}}\]

\[\Large \frac{1}{\left(5\right)^{2}}\]

\[\Large \frac{1}{25}\]

So \[\Large 125^{-\frac{2}{3}}=\frac{1}{25}\]