Question

(x+1)^2 would it be x^2 -1?

Answer 1

(x+1)^2

(x+1)(x+1)

x*x+x*1+1*x+1*1

x^2+x+x+1

x^2+2x+1

So (x+1)^2 expands out to x^2+2x+1

Answer 2

so then would (y-8)^2 be y^2+64?

Answer 3

No, (y-8)^2 = y^2 - 16y + 64 using the same idea