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Solve quadratic equation by completing the square. Check both roots. problem below
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\[2x^2-12x +16=0\]
please explain each step I am having trouble with it
2(x^2-6x+8)=0 2[(x-4)(x-2)]=0
please do explain why you do each step
1st step- Factor out 2. Second step- What 2 numbers add to the end value, and multiply to the middle value?
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Those 2 values are then put into the brackets as you see them.
And here, the signs of positive and negatives are reversed because when you solve for x individually, x-4=0 x=4. Ok?
ok but there is supposed to be two answers
4 is one of them
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