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what are the factors of 25t^2-1
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you could use the quadratic equation \[-b \pm \sqrt{b ^{2}-4ac } \over 2a\]
y = ax + b + c
\[ a^2 - b^2 =(a-b)(a+b)\\ 25 t^2 -1 =(5t-1)(5t+1) \]
^Yeah, use the difference of two squares method when you can.
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