Question

what are the solutions for x in the proportion 4x-3 over x + equal to 2x over 2

Answer 1

\[\frac{4x - 3}{x} = \frac{2x}{2}\]
Is that the problem?

Answer 2

Yes

Answer 3

Just cross multiply.
\[2x(x) = 2(4x - 3)\]
\[2x^{2} = 8x - 6\]
\[2x^{2} - 8x + 6 = 0\]
\[2(x^{2} - 4x + 3) = 0\]
Can you solve the quadratic?

Answer 4

I don't know how

Answer 5

\[2(x^{2} - 4x + 3) = 0\]
\[2(x - 3)(x - 1) = 0\]
Can you solve for x now?