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OpenStudy (anonymous):
What is the value of 4C2?
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OpenStudy (unklerhaukus):
six
OpenStudy (anonymous):
\[nCr = \frac{n!}{(n - r)! r!}\]
OpenStudy (anonymous):
4C2 \[=\frac{4!}{(4-2)!2!}\]\[=\frac{ 4!}{2!2!}\]\[ = 6\]
OpenStudy (anonymous):
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