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Mathematics 18 Online
OpenStudy (anonymous):

3x^3-4x^2-27x+36=0

OpenStudy (anonymous):

\[3x^3-4x^2-27x+36=0\]\[3x^3-27x-4x^2+36=0\]\[3x(x^2-9)-4(x^2-9)=0\]\[(3x-4)(x^2-9)=0\]\[(3x-4)(x-3)(x+3)=0\]\[(3x-4)=0 \ or \ (x-3)=0 \ or \ (x+3)=0\] Can you solve the,?

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