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to solve for X i could use this = (31) + 6 or x = -(31) + 6 problem:x^2 - 12x + 5 = 0 you may just say yes or no thx
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want a hint?
well yes
you forgot to take the square root of 31
once you had \((x-6)^2=31\) the next step was \(x-6=\pm\sqrt{31}\) not \(x-6=\pm31\)
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o so il use 2 instead of 6
no no you had it correct, you just forgot the square root
it is not \(-31+6\) but rather \(-\sqrt{31}+6\) and \(\sqrt{31}+6\)
you don't know the square root of 31, so just leave it in your answer
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