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7-5x(under radical)=8
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\(\sqrt{7-5x}=8\)?
yes
\(7-5x=8^{2}\) are you able to do it now?
\(7-5x=64\) => \(-5x= 54\) => \(x=...\)
Just a quick tip, @Mimi_x3 [you'e doing a great job] but when you see these questions with solving equations with radicals that you have to perform the opposite operation.
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I did perform the opposite operation..
so what is the correct way to do this problem?
I just showed you!
oh it didn't load. sorry
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