Question

2x^4-10x^2+8=0

Answer 1

2x^4-10x^2+8=0
Divide both sides by 2
x^4 - 5x^2 + 4 = 0
(x^4 -x^2) - 4x^2 + 4 =0
x^2 (x^2-1) - 4(x^2 -1) =0
(x^2 - 4)(x^2 - 1) =0
(x^2 - 4)=0 or (x^2 - 1) =0
x^2 = 4 or x^2 = 1
Can you solve x now?

Answer 2

it would be \[\sqrt{2}\] and

1?

Answer 3

nope.. it is
\(x=\pm 2\) or \(x=\pm 1\)

Answer 4

thank you so much! I have a huge load of math to do and being able to check is great!