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Solve: x2 + 3x = 28 {-7, 4} {-4, 7} {-7, -4} {7, 4}
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change into x^2 + 3x - 28 = 0 factor out
x^2 + 3x = 28 x^2 + 3x -28 =0 (x+7)(x-4) =0 (x+7)=0 or (x-4) =0 Can you solve it?
Can you explain in brief for the 2nd and 3rd step
x^2 + 3x -28 =0 x^2 + 7x - 4x - 28 =0 x(x+7) - 4(x+7) =0 (x-4)(x+7) =0 Do I make it clearer to you?
k thanks i made a mistake sorry :/
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