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Mathematics 8 Online
OpenStudy (anonymous):

ln sin^3 2x

OpenStudy (anonymous):

derivative?

OpenStudy (anonymous):

yep

OpenStudy (anonymous):

3cosec 2

OpenStudy (anonymous):

sorry its 3cosec^2 2

OpenStudy (anonymous):

first take the derivative of ln that gives you \[\frac{1}{\sin^3 (2x)}\] now take the derivative of sin^3...that's 3sin^2 (2x) cos(2x) now take the derivative of 2..which gives you 2 now combine all of those ;)

OpenStudy (anonymous):

thanks a bunch:))

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