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the function f(x)=tan(3/2x-pi/2) has: A) period pi/3 and asymptote at x=pi/3 B) period 2pi/3 and asymptote at x=0 C) period 2pi/3 and asymptote at x=pi/3 D) period pi/3 and asymptore at x=0
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please heelpp :)
The function f(x)=-3cos(2x+pi/4) has a. amplitude 3 and period pi b. amplitude 2 and period 2pi/3 c. amplitude 3 and period 4pi d. amplitude 3 and period 2pi I got A.
i say B... period of tanx is pi so period of tan(3/2x) is pi/(3/2) = 2pi/3
thankk you everyone. I agree with @dpaInc
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