Question

Find the inverse of each function.
y=log(base3)(x+8)
y=-9log(basex)4

Answer 1

x=y3-8

Answer 2

And elaborate, please.

Answer 3

y=log(base3)(x+8)
therefore, 3^y=x+8
interchanging x and y
3^x=y+8
or, Y=3^x -8
so, that's your inverse function for 1st one.

Answer 4

Can you try the other one in the similar way?

Answer 5

second is pre much the same
1/y = -1/9 log4 (x)

Answer 6

suno...power raise karne ka ulta logarithm karna hota hai. samjhe?

Answer 7

What would I do with the -9 for the second one?

Answer 8

take it to the power.
xlogy =logy^x

Answer 9

So it would be log(basex)4^-9?

Answer 10

yep

Answer 11

y=log(basex)4^-9
so x^y=4^-9?

Answer 12

yep!

Answer 13

And you interchange x and y, so y^x=4^-9 and solve for y and that's the answer?

Answer 14

yep!