a cyclist goes one round a circular track of siameter 105 metre in 5min calculate his speeed
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OpenStudy (anonymous):
...................?????????
OpenStudy (anonymous):
n the ans is ??
OpenStudy (anonymous):
2x pi x r/5 x60=1.1m/s
OpenStudy (anonymous):
1.1m ??
OpenStudy (anonymous):
can i ask u one more??
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OpenStudy (anonymous):
k yah!
OpenStudy (anonymous):
a machine gun fires 25 gm bullets at the rate of 600 bullets per min with a speed of 200m/s . calculate the force required to keep the gun in position.
OpenStudy (anonymous):
50N
OpenStudy (anonymous):
how??? can u do it here???
OpenStudy (anonymous):
yah, the change in momentum gives us the force! the bullets exert a force on the bullets which is 25x600/1000(200-0)/60=50 N.thus a force of 50N will keep the gun in equilibrium!
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OpenStudy (anonymous):
i meant that the bullets exert 50N on the gun!
OpenStudy (ujjwal):
@eccme in the answer to first qsn you forgot to convert min to sec. correct it!
OpenStudy (anonymous):
i did ujjwal!
OpenStudy (ujjwal):
oh, yeah. sorry, emerging physicist! you should have put them in parentheses. that confused me.
OpenStudy (anonymous):
oh ryt,cant beat ur eye for perfection friend!
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